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MakcuM [25]
3 years ago
9

C is equidistant from A and B. What is the value of x? A. 6 B. 8 C. 12 D. 14

Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0
The correct answer that i came up with is D
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Malik’s recipe for 4 servings of a certain dish requires 1/{1}/{2} cups of pasta. According to this recipe, what is the number o
Ostrovityanka [42]

Answer:

The answer to the question is

1\frac{1}{2} cups

Step-by-step explanation:

According to the recipe number of cups of recipe of past required = 1\frac{1}{2} cups

A recipe is a predefined steps and directions required to make an item mostly especially something to eat.

Recipe in medicine or Latin means to "take"  hence, a doctor usually writes on a prescription with a recipe, Latin for take and abbreviated as Rx or similar symbol.

In the original question, the number of cups of pasta that Malik will use the next time he prepares this dish is  1\frac{1}{2} cups

3 0
3 years ago
Which algebraic expressions are polynomials? Check all that apply. PLEASE HELP
dexar [7]
Selections 2, 3, 5, 6 are polynomials.

1 and 4 are not. The coefficients don't have to be integers, but the powers of the variables need to be positive integers. In 1, you have x^-1. in 4, you have x^(1/2).
3 0
3 years ago
Consider the planes 4x+3y+4z=1 and 4x+4z=0. (A) Find the unique point P on the y−axis which is on both planes. ( 0 equation edit
Nana76 [90]

Answer:

Step-by-step explanation:

A) From the order of the exercise we already know that the intersection points lies on the Y-axis, so its coordinates are P(0;y;0). In order to find it, we only need to substitute the equation 4x+4z=0 into the equation 4x+3y+4z=1. Then,

1=4x+3y+4z = 3y + (4x+4z)= 3y+0.

From the expression above it is easy to obtain that y=1/3, and the intersection point is P(0;1/3;0).

B) To obtain the parallel vector to both planes we use the cross product of the normal vector of the planes.

\left[\begin{array}{ccc}i&j&k\\4&3&4\\4&0&4\end{array}\right] = 12i-0j+12k

As we want a unit vector, we must calculate the modulus of u:

|u|=\sqrt{12^2+0^2+12^2} = \sqrt{2\cdot 12^2}=12\sqrt{2}.

Thus, the wanted vector is \frac{u}{12\sqrt{2}}. Therefore,

u = \frac{1}{\sqrt{2}}i-\frac{1}{\sqrt{2}}k = \frac{\sqrt{2}}{2}i-\frac{\sqrt{2}}{2}k.

C) In order to obtain the vector equation of the intersection line of both planes, we just need to put together the above results.

r = \frac{1}{3}j +\lambda \left( \frac{\sqrt{2}}{2}i- \frac{\sqrt{2}}{2}k \right)

where \lambda is a real number.

8 0
4 years ago
Please help ; ) graph is linked to this post
Flura [38]
The answer to the equation is Y=3f
6 0
3 years ago
What is the value of the expression <br> 4x+y<br> 2y−x <br> when<br> x = 2 and y = 4
Ivenika [448]

the first on is 12 and the second is 6. Hope this helped!! Could I possibly get brainliest!? :)

3 0
3 years ago
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