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Andru [333]
3 years ago
8

The ratio of an object's weight on Earth to its weight on Mars is 5 to 2. How much would a man, who weighs 145 pounds on Earth,

weigh on Mars?
Mathematics
1 answer:
butalik [34]3 years ago
6 0
To answer this youd have to set up a proportion. 5/2 is the ratio of weight on earth and mars respectively. The other side has to have the same ratio where 125lbs is the weight on earth and x is the weight on mars. The equation would look like 5/2=125/x. Youd have to cross multiply, and would get (125)(2)=5x. Solve for x to find the weight on mars
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Need help checking my answers
kifflom [539]

Answer:

Step-by-step explanation:

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Look at the photo below for the answer,

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6 0
3 years ago
X2 +5x+1<br> x 3x2 - 2x + 4
bulgar [2K]

Answer:

6x^2+5x+4

Step-by-step explanation:

hope this helps

5 0
3 years ago
If you rolled two dice what is the probability that you would roll a 4 or a 5
Masja [62]
Hello there! Given that normal dice are numbered 1-6, individually rolling a 4 or a 5 would give a 1/6 probability. That converts to about 17% as a percentage because we can multiply 1 by 100 to get 100/6, then divide 100 by 6 to get 16.6666. When rounding, that gives approximately 17%. However, if we combined probabilities, we would find that rolling a 4 or a 5 collectively gives a 2/6 probability, which is approximately 33% as a decimal.

In terms of individual probabilities, you would be 17% likely to roll one of them. In terms of collectiveness, the likelihood of rolling a 4 or 5 would render 33% on each die. If you need additional help, let me know and I will gladly assist you.
5 0
2 years ago
Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less
STALIN [3.7K]

Answer:

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter , hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2*(L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10  --->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2*(L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B  (2*B+ B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10= 26*2 - 10 = 52-10=42

length of house = 42  cm

Hence dimension of Brian's house is length 42 cm and width 26 cm

5 0
3 years ago
A<br> Find tan a.<br> r<br> √5,-√7)<br> ✓[?<br> Enter
Virty [35]

Answer:

tan(\alpha)=-\frac{\sqrt{35}}{5}

Step-by-step explanation:

Tan can be defined as: \frac{sin(\theta)}{cos(\theta)} as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.

Using this we can define tan

sin(\alpha)=-\sqrt{7}\\cos(\alpha)=\sqrt{5}\\\\tan(\alpha)=-\frac{\sqrt{7}}{\sqrt{5}} * \frac{\sqrt{5}}{\sqrt{5}}\\tan(\alpha)=-\frac{\sqrt{7*5}}{5}\\tan(\alpha)=-\frac{\sqrt{35}}{5}\\

8 0
2 years ago
Read 2 more answers
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