The process or activity of writing computer programs.
Answer:
All the three statements given are true so the correct option is option 4 which is none of the above.
Explanation:
The options are given in a jumbled up form the options are sorted which are as follows:
- SOA eliminates the use of application boundaries, the traditional methods where security is at the application level aren't likely to be effective
- An atomic service cannot be decomposed into smaller services that provide a useful function
- XML security service may be found in retail application communication.
- None of the mentioned
SOA stands for Service Oriented Architecture. This eliminates the application boundaries so option 1 is true.
An atomic service is defined as the smallest service which cannot be divided further. So this is true as well
The XML security service is incorporated in all retail applications. so this is true as well.
So the remaining option is just None of the mentioned.
The primary feature of a digital video camera is to records video as digital signals. A digital video camera picture out as of live settings, encrypting it into information that can be definite or transcoded into electronic photographic media. A typical digital camera contains of a lens, image sensor, storing media and a number of other characteristics that can be also be initiated on other cameras such as scalable aperture, filters and flash. High feature images and digital video slides can be put in storage and replicated on a computer, CD or writable DVD or on the internet in deprived of any loss of quality.
<span>Both computers are seen as having the same IP address externally. Your router will relay requests to the originating computer and the procedure used for this is Network address translation. However, if you were to try to communicating with your father's computer, you would use your internal addresses</span>
#include <stdio.h>
struct student {
char firstName[50];
int roll;
float marks;
} s[5];
int main() {
int i;
printf("Enter information of students:\n");
// storing information
for (i = 0; i < 5; ++i) {
s[i].roll = i + 1;
printf("\nFor roll number%d,\n", s[i].roll);
printf("Enter first name: ");
scanf("%s", s[i].firstName);
printf("Enter marks: ");
scanf("%f", &s[i].marks);
}
printf("Displaying Information:\n\n");
// displaying information
for (i = 0; i < 5; ++i) {
printf("\nRoll number: %d\n", i + 1);
printf("First name: ");
puts(s[i].firstName);
printf("Marks: %.1f", s[i].marks);
printf("\n");
}
return 0;
}
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