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Mice21 [21]
3 years ago
13

Help pleaseee Im trying to get an A in class

Mathematics
1 answer:
likoan [24]3 years ago
3 0

Answer:

191

Step-by-step explanation:

Sorry it's sideways. I drew a box chart for this. First, fill in what you know: the number of white and black beads Ally has. Then, calculate how many black beads Betty has (Ally's number, 59, minus 35.) 59-35 = 24.

They tell you the total number of beads is 346. Add up Ally's total to get 131, then subtract that from 346. That's Betty's total beads, 215.

Last, subtract the 24 black beads Betty has from the 215 total to get 191.

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Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4% of the total inter
noname [10]

Given

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4%.

Total interest paid was $475

Find out  he invest in each.

To proof

Let us assume that Paul invested  in an account paying 4% be = x

As given in the question

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4%.

Let us assume that Paul invested  in an account paying 5% be = 3x

Total interest paid = $475

First convert 4% in the decimal form

=\frac{4}{100}

= 0.04

First convert 5% in the decimal form

=\frac{5}{100}

= 0.05

Than the equation become in the form

0.04x + 0.05 × 3x = 475

0.04x + 0.15x = 475

0.19x = 475

x = $2500

Paul invested  in an account paying 4% be = $2500

Paul invested  in an account paying 5% be = $7500

Hence proved






5 0
3 years ago
What is the answer to 3 3/4+ 2 9/16
Andrews [41]

Answer:

This is the answer of your question 6.3125

8 0
3 years ago
7......:.:.:.:.....:.:.:;;::;..:::
Jobisdone [24]

Round 6.667616

= 7

Answer: A) 7

3 0
3 years ago
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
3 years ago
Can someone help me please
bija089 [108]

answer:

oops, I accidentally messed this one up, so sorry

7 0
2 years ago
Read 2 more answers
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