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Ber [7]
3 years ago
7

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4% of the total inter

est paid was $475 how much did he invest in each
Mathematics
1 answer:
noname [10]3 years ago
5 0

Given

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4%.

Total interest paid was $475

Find out  he invest in each.

To proof

Let us assume that Paul invested  in an account paying 4% be = x

As given in the question

Paul invested three times as much money in the account paying 5% interest then he did in an account paying 4%.

Let us assume that Paul invested  in an account paying 5% be = 3x

Total interest paid = $475

First convert 4% in the decimal form

=\frac{4}{100}

= 0.04

First convert 5% in the decimal form

=\frac{5}{100}

= 0.05

Than the equation become in the form

0.04x + 0.05 × 3x = 475

0.04x + 0.15x = 475

0.19x = 475

x = $2500

Paul invested  in an account paying 4% be = $2500

Paul invested  in an account paying 5% be = $7500

Hence proved






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Answer:

(a) The value of <em>x</em> is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = <em>x</em>.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, \sum P(X)=1

Compute the value of <em>x</em> as follows:

\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

P(A^{c})=1-P(A)

Compute the probability that a reported case of rabies is not a raccoon as follows:

P(R^{c})=1-P(R)\\=1-0.55\\=0.45

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

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3 years ago
Determine whether the triangles are similar. or not.
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Answer:

B.Similar,sss

Step-by-step explanation:

Since no angles measures are provided in these triangles, we can determine if these triangles are similar by using the SSS Similarity Theorem. This requires that we determine if each pair of corresponding sides have an equal ratio.

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This graph shows a proportional relationship.<br> What is the constant of proportionality?
Vlad1618 [11]

Answer:

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Step-by-step explanation:

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2 years ago
Given two events A and B of a sample set where P[A] = .20 P[not B] = .40 P[B|A] = .25 What is P[A or B]?
kobusy [5.1K]

Answer:

Given two events A and B of a sample set :-

P[A] = 0.20  

P[not B]=0.40

P[B/A]=0.25

To find P[A or B]:

P[A or B] = P[A] + P[B] - P[A \cap B]                ......[1]

Calculate for P[B] and P[A \cap B]

P[B] = 1- P[not B]

Substitute the value P[not B] we get;

P[B] = 1-0.40 = 0.60      

P[A \cap B] = P[B/A] \cdot P[A]

Substitute the given values we get;

P[A \cap B] = 0.25 \cdot 0.20 = 0.05

Then;

P[A or B] = 0.20+0.60-0.05 = 0.80-0.05 =0.75

Therefore, the value of P[A or B] is, 0.75.


8 0
2 years ago
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Answer:

type question correctly

Step-by-step explanation:

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