this is a binomial problem: p = 0.7 and q = 0.3
a) (0.7)^6
b) (6C4)(0.7)^4(0.3)^2
c) Pr ( at least 4) = Pr(4) + Pr(5) + Pr(6) = (6C5)(0.7)^5(0.3) + (0.7)^6
d) Pr (no more than 4) = 1 - Pr(at least 4) = 1 - (answer from c)
C. 51* I am pretty sure is it
Answer:
given
hope it helps!
Step-by-step explanation:
(10x^3y^2/5x^-3y^44)
= (10/5)(x^3/x^-3)(y^2/y^44)
= (2)(x^6)(y^-42)
= 2x^6y^-42
(2x^6y^-42)^3
= 8x^6*3y^-42*3
= 8x^18y^-126
Answer:120.430 US Dollars
Step-by-step explanation:
Answer:
B is the answer
Step-by-step explanation:
Look at where the decimal is placed and the value of the numbers