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Ahat [919]
2 years ago
6

A large container holds 14 litres of a solution which is 25% antifreeze, the remainder being water. How many litres of antifreez

e must be added to the container to make a solution which is 30% antifreeze? NOTE: Only put number, DO NOT PUT any units or sentences.
Mathematics
1 answer:
frutty [35]2 years ago
5 0

Answer:

2.8 liters

Step-by-step explanation:

So there are various ways to do this problem, this is just MY preferred way.

Since we are given 1/4th of a total value with 14 liters, we can actually make this 4/4 by multiplying our given value by 4. In this case, 14 liters for 25% becomes 56 liters for 100% antifreeze.

Since we know have a percent of 100%, we can proceed to take 10% increments, all the way up to 30%

10% is 5.6, multiplied by 3 is 16.8

While you might want to put 16.8 instantly, don't forget we are looking for how much is ADDED from 25%, not just how much there is.

In this case, subtract 14 from 16.8 to come out with a grand total of 2.8 liters added.

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1) 1: 107

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Step-by-step explanation:

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Answer:

The value of given expression i.e Ф is 90°  and - 30°

Step-by-step explanation:

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or, 2 sin²Ф - 2 sinФ +  sinФ - 1 = 0

Or, 2 sinФ ( sinФ - 1 ) + 1 ( sinФ - 1 ) = 0

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Or,  sinФ = - \frac{1}{2}

Or,   Ф = sin^{-1}(-\frac{1}{2}) = - 30°

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