Answer:
Step-by-step explanation:
Hello,
Let's develop both expressions and try to re factorise.
Thanks
Answer:
56.7°
Step-by-step explanation:
A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?
We solve this question using the Trigonometric function of Sine
From the question, we are told that:
A rectangle is 5.1 cm wide
and each diagonal is 9.3 cm long.
Since we have a diagonal, this means the shape is transformed to a triangle.
The width of the rectangle = Adjacent side of a triangle = 5.1cm
The diagonal of the rectangle = Hypotenuse = 9.3cm
Hence,
cosθ = Adjacent/Hypotenuse
cosθ = 5.1/9.3
cosθ = 0.5483870968
θ = arccos(0.5483870968)
θ = 56.743568714°
Approximately = 56.7°
The measure of the angle is 56.7°
Answer:
Step-by-step explanation:
a) 4/9*x^4
b) 2/y
Answer:
2
Step-by-step explanation:
Perimeter of a rectangle = 2(length + breadth)
=> 2{2x + (x + 4)) = 20
=> (2x + x + 4) = 20/2 = 10
=> 3x + 4 = 10
=> 3x = 10 - 4 = 6
=> x = 6/3 = 2
Here, according to the diagram
Length = 2x = 2(2) = 4
Breadth = x + 4 = 2+4 = 6
But breadth should always be lesser than the length. From this, it can be concluded that the actual breadth is 2x and actual length is x + 4, for perimeter to be 20.
Answer:
tan
Step-by-step explanation:
take 19 degree as reference angle
using tan rule
tan 19=opposite/adjacent
0.34=14/x
x=14/0.34
x=41.17
x=41.2
