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AysviL [449]
4 years ago
15

Divide 4p2 + 6 by 2p – 2. Which statements are true about the division? Select three options. The divisor is 2p – 2. The dividen

d is 4p2 + 0p + 6. The quotient is 2p + 2 + . The remainder over the divisor is . To check the answer, multiply 2p + 2 + times 4p2 + 0p + 6 and verify that it equals the divisor.
Mathematics
1 answer:
Dahasolnce [82]4 years ago
5 0

Answer:

The answer to your question is below

Step-by-step explanation:

1.

                                           2p    +  2                       ⇒  Quotient

Divisor    ⇒     2p - 2        4p²   +   0p  +  6            ⇒ Divident

                                        -4p²    +   4p

                                           0      +  4p  + 6

                                                   -  4p   + 4

                                                        0   + 10             ⇒ Remainder

2. The dividend is 4p2 + 0p + 6.

The quotient is 2p + 2 + .

The remainder over the divisor is     10 / (2p - 2)  .

To check the answer, multiply 2p + 2 + times 4p2 + 0p + 6 and verify that it equals the divisor.

                  (2p - 2)(2p + 2) = 4p⁴ + 4p - 4p - 4

                                           = 4p⁴ - 4 + 10

                                          = 4p⁴ + 10

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Jerome found the lengths of each side of triangle QRS as shown, but did not simplify his answers. Simplify the lengths of each s
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Answer:

QR = 6.0033

QS = 8.22

RS = 6.0033

QRS is isosceles

Step-by-step explanation:

Given

See attachment for complete question

From the attachment, we have the following parametersQR = \sqrt{(-3-0)^2+(-5.2-0)^2}

QR = \sqrt{9+27.04}

QS = \sqrt{(-3-5)^2+(-5.2-(-3.322))^2}

QS = \sqrt{64+3.53} = \sqrt{67.53

RS = \sqrt{(0-5)^2 + (0 - (-3.322))^2}

RS = \sqrt{(25 + 11.04}

Solving further, we have:

QR = \sqrt{9+27.04}

QR = \sqrt{36.04}

QR = 6.0033

QS = \sqrt{64+3.53} = \sqrt{67.53}

QS = 8.22

RS = \sqrt{25 + 11.04}

RS = \sqrt{36.04}

RS = 6.0033

From the calculations;

RS = QR = 6.0033

<em>This means that: QRS is isosceles</em>

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Let r be the common ratio between terms. Then

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Now denote the nth partial sum of the series by

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