Answer:
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- <u>36 cubes</u>
- <u>There are several forms to figure it out: see two different ways explained below.</u>
Explanation:
The first way to figure out <em>how many more cubes Jill will need to add to complete the structure </em>until forming a <em>rectangular prism</em> is to add the cubes from column to colum,
The first column is complete: it has four rows each with 4 cubes.
The second column (the one next to the right of the first column) has three rows. Then Jill has to add one more row. This is 4 cubes.
The third column has two rows. Then, Jill will need to add two rows with 4 cubes each, for a total of 8 cubes. So far, the count is 4 + 8 = 12 cubes.
The fourth and fifth columns have just one row. Then, Jill will need 3 rows for each column, making it 2 × 3 × 4 = 24 cubes.
The total final count is 12 + 24 = 36 cubes. ← answer
There are different ways to figure out the number of cubes needed to complete the rectangular prism. This is another one:
How many cubes shall the complete pyramid have? : 4 × 4 × 5 = 80 (length × width × height).
How many cubes does the shown incomplete structure have?: 4×4 + 3×4 + 2×4 + 4 + 4 = 16 + 12 + 8 + 4 + 4 = 44.
Difference: 80 - 44 = 36 cubes. ← answer
Answer:
The answer is table C represnts a non funtion
Step-by-step explanation:
Table A, B, D don't repeat any numbers. But Table C has Two 24's in it.
Use the fact that integrals are additive on their intervals. Mathematically, if ![c\in[a,b]](https://tex.z-dn.net/?f=c%5Cin%5Ba%2Cb%5D)
, then
So we have
Answer:
This is not correct
Step-by-step explanation:
He could have rolled a 6 on the second roll without rolling a 6 on the first roll, the first roll had ZERO effect on the second one to be able to change what he would roll
I don't understand what you need.
But,
5 + 3 = 8
56/8 = 7
7*5 = 35
7*3 = 21
Hope this helps !
Photon
