Answer:
The probability that the town has 30 or fewer residents with the illness = 0.00052.
Step-by-step explanation:
So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.
The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.
Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.
Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness = e^-λ × λ^x/ x!
The team plays 20 matches.
65% of the matches, the teams wins
= 20 * 0.65
= 13 matches
15% of the matches, the games ends in draw.
= 20 * 0.15
= 3 matches
The team is expected to lose in
= 20 - 13 - 3
= 4 matches
X = -3, y = 2..................
Answer:(2k-1)(k-12)
Step-by-step explanation:
