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3 years ago

Solve the problem 6=-w/8 The slash means it is a fraction.

Mathematics

1 answer:

guapka [62]3 years ago

7 0

48/8 can equal 6. I hope this helps!

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Apply the distributive property and the greatest common factor to write an equivalent expression.

amid [387]

Here, Your Original expression is 60x - 24.

Take 12 as common, which is GCD of 24 & 60,

Therefore, It would be:

60x - 24
= 12 * 5x - 12 * 2
= 12 (5x - 2)

In short, your Answer would be 12(5x - 2)

Hope this helps!

Photon

5 0

3 years ago

Help me!! don’t give me the sample response though!

REY [17]

Answer:

They are both correct because, they both used the properties of equality.

Step-by-step explanation:

7 0

2 years ago

The quotient of six and one

Nastasia [14]

A quotient of a number and 6

Explanation: Quotient means that you divide something by another. Let's let n be the "number". Therefore, "a quotient of a number and 6" refers to n6 or n÷6 .

6 0

2 years ago

Read 2 more answers

50 POINTS PLS HELP

egoroff_w [7]

Answer:

Step-by-step explanation:

find value at 12 =12

find value at 10 = 6

so it changes + 6 for a change from 10 to 12

6/2 = 3

4 0

2 years ago

Read 2 more answers

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago