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yaroslaw [1]
3 years ago
10

Maria has scores of 96, 86, and 78 on three test. What must her average score be in order for her to have an average of at least

90?
Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Marks scored in three tests = 96 , 86 , 78

Total of these scores = 260

Let the score that needs to be scored be = x

Average needed of four scores = 90

Average = total scores added of all subjects/number of subjects

\frac{96+86+78+x}{4}=90

260+x=360

x=100

Hence, a score of 100 is required to make an average score of 90.


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For a circle with a radius of 15 cm, what is the length of an arc intercepted by an angle measuring 120°?
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Given: m∠EYL=72°<br> Find: mEHL , mLVE
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Answer:

Part 1) The measure of arc EHL is 108\°

Part 2) The measure of angle LVE is 54\°

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

so

m

we have

m

substitute

72\°=\frac{1}{2}(y-x)

144\°=(y-x)

y=144\°+x ------> equation A

Remember that

x+y=360\° -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

x+(144\°+x)=360\°

2x=360\°-144\°

x=216\°/2=108\°

Find the value of y

y=144\°+x

y=144\°+108\°=252\°

therefore

The measure of arc EHL is 108\°

The measure of arc EVL is 252\°

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

m

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