I think the correct answer is C.
2cos(x) - 4sin(x) = 3
use identity [cos(x)]^2 +[ sin(x)]^2 = 1 => cos(x) = √[1 - (sin(x))^2]
2√[1 - (sin(x))^2] - 4 sin(x) = 3
2√[1 - (sin(x))^2] = 3 + 4 sin(x)
square both sides
4[1 - (sin(x))^2] = 9 + 24 sin(x) + 16 (sin(x))^2
expand, reagrup and add like terms
4 - 4[sin(x)]^2 = 9 + 24sin(x) + 16sin^2(x)
20[sin(x)]^2 + 24sin(x) +5 = 0
use quadratic formula and you get sin(x) = -0.93166 and sin(x) = -0.26834
Now use the inverse functions to find x:
arcsin(-0.93166) = 76.33 degrees
arcsin(-0.26834) = 17.30 degrees
No its not a prime number its actually a square number.
<h2>Answer: 15/14</h2><h2>_____________________________________</h2><h3>Honey, all you need to do is substitute the value of the variable into the equation and simplify!</h3><h3>To get the answers:</h3><h3>Exact Form:</h3><h3>15/14</h3><h3>Decimal Form:</h3><h3>1.07142857…</h3><h3>Mixed Number Form:</h3><h3>1 1/14</h3><h2>_____________________________________</h2><h3>Hope you have a good day, Loves!~ <3</h3>
