This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Answer:
2 degrees and 178 degrees.
Step-by-step explanation:
So, remember if 2 angles are supplementary, they equal 180 degrees. Let's call the smaller angle x, meaning the bigger angle, which is 89 times the size of the smaller angle, would be 89x. Now let's put that into an equation.
180 = x + 89x
We now have to group the x's together:
180 = 90x
Now in order to determine x, we have to divide by 90 on both sides.
X= 2
So we know that the smaller angle is 2, meaning that if the larger angle is 89 times the size, the larger angle would be 178.
Answer:
Gender, car
Step-by-step explanation:
Give the data above :
The categorical variables are : Gender and Car
The Gender are car variables represents non numeric variables written as strings and as such does not allow for numeric calculations such as addition, subtraction and so on, they are instead used to classify the observations in the data into discreet groups, the gender variable separates observations into Male and Female classes while, the car variable separates cars driven into distinct classes denoting the name of cars driven by each observation in the data. The other variables are of quantitative nature as they allow for numerical computation of the data values.
Answer:
D
Step-by-step explanation:
