Can you please help me with this very hard math problem?

Mathematics

2 answers:

padilas [110]3 years ago

6 0

Answer:

how would I solve this monstrosity

ElenaW [278]3 years ago

5 0

Sorry man I can’t answer that the screen is too dark (I DONT MEAN TO BE RACIST)

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Write an equation in slope-intercept form of the line with the given parametric equations,

Alex_Xolod [135]

The equation in slope-intercept from is y = $\frac{9}{8}x - \frac{3}{8}$ .

Step-by-step explanation:

Given,

x = 8t+3

y= 9t+3

First, convert both the equations in terms of t for comparison.

x = 8t + 3

x - 3 = 8t

t = $\frac{x-3}{8}$

Similarly,

y = 9t + 3

y - 3 = 9t

t = $\frac{y-3}{9}$

Now, comparing both equations

$\frac{x-3}{8}$ = $\frac{y-3}{9}$

9x -27 = 8y -24

9x - 3 = 8y

y = $\frac{9}{8}x - \frac{3}{8}$

Hence, the equation in slope-intercept from is y = $\frac{9}{8}x - \frac{3}{8}$ .

3 0

3 years ago

Use these functions to answer the questions.

Elenna [48]

Part A
We have $f\left(x\right)=\left(x+3\right)^2-1$ . To solve for the x-intercept, we set f(x) equal to 0. That is
$\left(x+3\right)^2-1=0$

$\left(x+3\right)^2=1$

Take the square root of both sides,
$x+3=1$

$x=-2$

The x-intercept is (-2,0).

To solve for the y-intercept, we set x=0. That is
$y=\left(0+3\right)^2-1=3^2-1=9-1=8$

The y-intercept is (0, 8)

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have $g\left(x\right)=-2x^2+8x+3$ .
Factor out -2
$=-2\left(x^2-4x\right)+3$

Complete the square
$=-2\left(x^2-4x+4\right)+3-2\left(4\right)$

Simplify
$g(x)=-2\left(x-2\right)^2-5$

Part C
We have $h\left(t\right)=-16t^2+28t$ .
The maximum height is 12.25 feet after 0.875 seconds from the time of the jump. The dolphin will be back in the water after 1.75 seconds. The graph of the jump is shown in the photo.