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jok3333 [9.3K]
3 years ago
9

Concentration cell based on the Ni2 -Ni cell reaction.

Biology
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

Explanation:

The missing diagram contained in this question is first attached in the image below.

The objective of this question is to determine how ions migrate when the cells are operating by assuming the solutions are composed of Ni(NO3)2.

From the information provided:

In this instance, the ions tend to move first from cathode to anode in terms of raising the concentration of Ni(2+) at the anode, resulting in the development of a dead cell. The initial concentration of [Ni(2+)] in the anode solution is 1.00 × 10⁻³ M, which gradually increases to 0.5 M, during which both the cathode and the anode possess the same concentration at the same point.

This causes Q(equilibrium constant) to equal  1 as well as log(Q) to equal 0, indicating that the cell is dead.

As a result, the cell will cease to operate, and nothing will migrate from the left to the right side.

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<u>Complete question goes like this</u>, "<em>The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If acetyl-CoA is labeled with 14C at the carbonyl carbon, how many rounds of the cycle are required before 14CO2 is released?</em>"

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