2 years ago

How many solutions does the following system have

Mathematics

1 answer:

Akimi4 [234]2 years ago

6 0

Answer:

C) One solution: $(\frac{1}{3}, 0)$

Step-by-step explanation:

Hope this helps!

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B(1)= -12

Leto [7]

Given:

$b(1)=-12$

$b(n)=b(n-1)\cdot 4$

To find:

The third term of the sequence.

Solution:

We have,

$b(n)=b(n-1)\cdot 4$

For n=2, we get

$b(2)=b(2-1)\cdot 4$

$b(2)=b(1)\cdot 4$

$b(2)=-12\cdot 4$ $[\because b(1)=-12]$

$b(2)=-48$

For n=3, we get

$b(3)=b(3-1)\cdot 4$

$b(3)=b(2)\cdot 4$

$b(3)=-48\cdot 4$ $[\because b(2)=-48]$

$b(3)=-192$

Therefore, the 3rd term of the sequence is -192.

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