Answer:
AB = 142
Step-by-step explanation:
If M is the midpoint, then AM = MB
6x+5 = 7x -6
Subtract 6x from each side
6x-6x+5 = 7x-6x -6
5 = x-6
Add 6 to each side
5+6 = x-6+6
11=x
We want to find AB
AB = 6x+5+7x-6
AB = 13x -1
= 13(11) -1
=143-1
= 142
Answer:
r(-1) = 6.31 and r(2) = -16.88
Step-by-step explanation:
* Lets read the problem and solve it
- Evaluate means find the value, so evaluate r(x) means find the value
of it at the given values of x
∵ r(x) = -0.21x³ + x² - 8.1x - 3
∵ x = -1 and x = 2
- Then find r(-1) by substitute x by -1 and find r(2) by substitute x by 2
# At x = -1
∴ r(-1) = -0.21(-1)³ + (-1)² - 8.1(-1) - 3
∴ r(-1) = -0.21(-1) + (1) - 8.1(-1) - 3
∴ r(-1) = 0.21 + 1 + 8.1 - 3
∴ r(-1) = 6.31
# At x = 2
∴ r(2) = -0.21(2)³ + (2)² - 8.1(2) - 3
∴ r(2) = -0.21(8) + (4) - 8.1(2) - 3
∴ r(2) = -1.68 + 4 - 16.2 - 3
∴ r(2) = -16.88
* r(-1) = 6.31 and r(2) = -16.88
Answer:
15+c=17.50 First you subtract 15 by 15 because you switch operations from adding to subtracting then you would put C under it Second subtract 17.50 and 15 and that is 2.50 so C= 2.50
i need help please What is the total number of drawSprites(); you can have in a program? *
Step-by-step explanation:
Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
.
To find:
The 
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]
In triangle AOB,
Therefore, the measure of angle AOB is 120 degrees.
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
