Question

X varies directly as the cube root of y .x=6when y=8.Find the value of x when y=64.

Answer 1

Answer:

The value of x is 12.

Step-by-step explanation:

Given that x is directly proportional to y so the expression will be x = k (³√y) where k is the constant. First, you have to find the value of k :

$x = k \: (\sqrt[3]{y} )$

$let \: x = 6,y = 8$

$6 = k \: (\sqrt[3]{8} )$

$6 = k(2)$

$k = 3$

Next, you have to find the value of x, by substituting y = 64 into the expression :

$x = 3 \: ( \sqrt[3]{y} )$

$x = 3( \sqrt[3]{64} )$

$x = 3(4)$

$x = 12$