The number of half dollars coins are 5 and the number of the quarters dollars coins are 12.
<h3>What is the linear system?</h3>
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
You have a cup with 17 coins inside.
The total inside the cup is $5.50.
Let x be the number of half dollars and y be the number of the quarters dollars.
Then the equations will be
x + y = 17 ............1
0.5x + 0.25y = 5.5 ...........2
By solving equations 1 and 2, we have
x = 5 and y = 12
More about the linear system link is given below.
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Answer: A
Step-by-step explanation:
Take 2 equations that make one of their letters disappear, and add them up:
2x + y + z = 1
x - y + 4z = 0
------------------------
3x + 5z = 1
Do the same with another 2 equations in which the letter, in this case y, can be removed. If you can't, take 2 of 3 equations and equal the value of the letter to make it eliminable.
x - y + 4z = 0
x + 2y - 2z = 3
Since we can't eliminate y, we have multiply as necessary to make it eliminable:
2 (x - y + 4z = 0)
= 2x - 2y + 8z = 0
add all up:
2x - 2y + 8z = 0
x + 2y - 2z = 3
-----------------------------
3x + 6z = 3
Now we've gone from a 3-variable equation to a 2-variable equation.
3x + 5z = 1
3x + 6z = 3
We can solve again by elimination; to get rid of z, for example, we cross multiply. the upper equation by 6 and the lower equation by 5. However, we have to make one of them negative in order to make them eliminable.
6 (3x + 5z = 1)
-5 (3x + 6z = 3)
----------------------------
18x + 30z = 6
-15x - 30z = -15
---------------------------
3x = - 9
Solving for x;
x = 
x = - 3
After finding one variable, we can use our 2-variable equations to find the next variable:
3x + 5z = 1
3 (-3) + 5z = 1
- 9 + 5z = 1
5z = 1 + 9
5z = 10
z = 
z = 2
Having found these 2 variables, we can put them into one of our main 3-variable equations to find the last one:
2x + y + z = 1
2(-3) + y + 2 = 1
- 6 + y + 2 = 1
y - 4 = 1
y = 1 + 4
y = 5
And you've found all the variables in the equation; to prove if they're correct or not, you can replace them in any of the main equations and the result should be equal to each other:
x + 2y - 2z = 3
-3 + 2(5) - 2(2) = 3
- 3 + 10 - 4 = 3
10 - 7 = 3
3 = 3
Answer:
Step-by-step explanation:
marked down by 1/4 of the original price.
let x represent original price
original price - 1/4 of original price = sales price
x - 1/4x = 128
4/4x - 1/4x = 128
3/4x = 128
x = 128/(3/4)
x = 128 * 4/3
x = 512/3
x = 170.666 rounds to 170.67 <== original price
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I hope I am understanding this one correctly...
let x = price the store paid
x + 1/2x = 170.67
2/2x + 1/2x = 170.67
3/2x = 170.67
x = 170.67 / (3/2)
x = 170.67 * 2/3
x = 341.34/3
x = 113.78 <=== what the store paid
===========================
the difference between the discount price..I am assuming this is the $ 128 from part A.....and what the store paid....113.78...from part B..
128 - 113.78 = $ 14.22 <==
I am not completely sure about B and C......B confused me.....and if B is wrong, so is C.