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jok3333 [9.3K]
2 years ago
5

Solve for s. -7 = 7s + 28

Mathematics
2 answers:
Zinaida [17]2 years ago
6 0

Answer:

s=  -5

Step-by-step explanation:

have a good day

Dvinal [7]2 years ago
3 0

Answer:

Step-by-step explanation:

subtract 28 on both sides that will cancel the 28

-35 = 7s, divide both sides by 7, this cancels the 7

- 5 = s

s=-5

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3 years ago
For f(x) = 4x + 2 and g(x) = x^2 - 6, find (f+g)(x)
Margaret [11]

Answer:

(f+g)(x) = x^2 + 4x - 4

Step-by-step explanation:

We are given these following functions:

f(x) = 4x + 2

g(x) = x^2 - 6

(f+g)(x)

We add the common terms. Thus:

(f+g)(x) = f(x) + g(x) = 4x + 2 + x^2 - 6 = x^2 + 4x + 2 - 6 = x^2 + 4x - 4

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Step-by-step explanation:

7 0
3 years ago
Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
2 years ago
Sarah's mom takes the parkway to work it takes her 30 minutes to travel from mile marker 88th where she answers to her exit at m
pentagon [3]
121- 88 = 33 miles traversed in 30 minutes.
 
d = r*t
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Solve for r. Average speed will be in miles per hour. <span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
7 0
3 years ago
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