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GuDViN [60]
3 years ago
11

a tourist drove his car for the total of 17.5 hours while on a 3-day vacation on the first day he drove 4.5 hours in the second

day he drove for 2.5 times as many hours as he drove on the first day how many hours did the tourist drive on the third day of his vacation (HELP PLEASE)​
Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

1.75 hours

Step-by-step explanation:

Time for day 1 : 4.5 hrs

Time for day 2: (4.5 ×2.5)

Time for day 3: let it be denoted by a variable ,say T.

Total Time= 17.5

(Time for day 1 ) + (Time for day 2) +(Time for day 3) =17.5

4.5 + (4.5×2.5) + T = 17.5

4.5+11.25+T =17.5

15.75+T=17.5

T=17.5-15.75

T= 1.75

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g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur
sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

\displaystyle V = \pi r^2h

Substitute:

\displaystyle (300) = \pi r^2 h

Solve for <em>h: </em>

\displaystyle \frac{300}{\pi r^2} = h

Recall that the surface area of a cylinder is given by:

\displaystyle A = 2\pi r^2 + 2\pi rh

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r}  \end{aligned}

Find its derivative:

\displaystyle A' = 4\pi r - \frac{600}{r^2}

Solve for its zero(s):

\displaystyle \begin{aligned} (0) &= 4\pi r  - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

\displaystyle  \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2}  \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm}   \end{aligned}

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0
3 years ago
HELP ASAP I DONT GET IT ITS DUE IN 14 MINS
Oksanka [162]

Answer:

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Step-by-step explanation:

just me doing work vvvvv

65 + 45.5 = 110.5

---

7 x 6.5

45.5

7 0
3 years ago
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Answer:

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Profit is represented by P.

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Find the product. (- d + 4)(- d - 4)
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