Answer:
1+6i
Step-by-step explanation:
Given:
f(x)=x^4 - 2x^3 + 38x^2 - 2 + 37
zero of f(x) = 1-6i
another zero of function = ?
Conjugate Zero theorem:
As per conjugate zero theorem, if a function f(x) has real coefficients and one of zero is a complex number then the conjugate of that complex number will also be a zero of that function i.e. complex zeroes will occur in complex conjugate pairs.
conjugate of 1-6i is 1+6i
hence another zero of f(x) will be 1+6i !
I maybe totally wrong but i want to say either A or C. A nonreal number is any number that when multiplied by itseld produces a negative number.
Answer:
20.1
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
2a + 2 / a = 4
2a + 2 = 4a
4a - 2a = 2
2a = 2
a = 1
2a² + 2 / a²
a = 1
2(1²) + 2 / 1²
2 + 2 / 1
4
Answer:
the second statement is not true
Step-by-step explanation:
If x squared equals 100, it doesn't mean necessarily that x is positive ten, since you can get 100 also by squaring the value (-10):
(-10)
The second statement is ignoring the possibility of x being a negative ten which also gives 100 as answered when squared.
