What is the area of the triangle that has vertices (-3,2), (5,6) and (-3,10)?
1 answer:
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QUESTION 3
The sum of the interior angles of a kite is .
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But the two remaining opposite angles of the kite are congruent.
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QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;
QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;
QUESTION 7
The sum of the interior angles of a kite is .
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But the two remaining opposite angles are congruent.
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QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;
QUESTION 9.
The sum of the interior angles of a trapezium is .
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But the measure of angle M and K are congruent.
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Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
