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2 years ago

C-1 1/4>-2 1/2 please help me

Mathematics

1 answer:

pentagon [3]2 years ago

7 0

I believe your answer should be C > -5/4

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Which expression gives the surface area of a sphere with radius r

ohaa [14]

Answer:

Simple, 4*pi*r^2

Step-by-step explanation:

6 0

3 years ago

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What are the zeros of f(x) = x3 + 6x2 + 3x – 10 ?

schepotkina [342]

One of the zeroes would be : x = 1

f (1) = 1^3 + 6(1) ^2 + 3 (1) - 10

f(1) = 1 + 6 + 3 - 10

f (1) = 10 - 10

f (1) = 0

Hope this helps

3 0

3 years ago

Katrina buys a 42-ft roll of fencing to make a rectangular play area for her dogs.

vekshin1

Answer:

(a) $l = -w + 21$

(b) Domain: $0$ (See attachment for graph)

Step-by-step explanation:

Given

$2(l + w) = 42$

$l = length$

$w = width$

Solving (a): A function; l in terms of w

All we need to do is make l the subject in $2(l + w) = 42$

Divide through by 2

$l + w = 21$

Subtract w from both sides

$l + w - w = 21 - w$

$l = 21 - w$

Reorder

$l = -w + 21$

Solving (b): The graph

In (a), we have:

$l = -w + 21$

Since l and w are the dimensions of the fence, they can't be less than 1

So, the domain of the function can be $0$

--------------------------------------------------------------------------------------------------

To check this

When $w = 1$

$l = -1 + 21$

$l = 20$

$(w,l) = (1,20)$

When $w = 20$

$l = -20 + 21$

$l = 1$

$(w,l)= (20,1)$

--------------------------------------------------------------------------------------------------

See attachment for graph

Solving (c): Write l as a function $f(w)$

In (a), we have:

$l = -w + 21$

Writing l as a function, we have:

$l = f(w)$

Substitute $f(w)$ for l in $l = -w + 21$

$l = -w + 21$ becomes

$f(w) = -w + 21$

5 0

3 years ago

Write 6x-7y=-84 in slope-intercept form

Anarel [89]

6x-7y=-84
7y = 6x + 84
y = 6/7(x) + 12

8 0

3 years ago

The length of a rectangle is 2 meters more than its width. The area of the rectangle is 80 square meters. What is the length and

insens350 [35]

Answer:

Step-by-step explanation:

Formula

A = L * W

Givens

W = W

L = W + 2

Solution

Area = L*W

Area = (W+2)*W = 80 Remove the brackets.

Area = W^2 + 2W = 80 Subtract 80 from both sides.

Area = w^2+2W-80=80-80 Combine

Area = w^2 +2W-80 = 0 Factor.

Area = (w+10)(w - 8) = 0

W + 10 = 0 won't work

W = - 10 which isn't possible

W- 8 = 0

W = 8

L = 8 + 2 = 10

The answer looks like A

8 0

3 years ago