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2 years ago

Help me i really need this .no spam

Mathematics

1 answer:

Naya [18.7K]2 years ago

4 0

<u>Question</u> : 8

$11 \sqrt{5} + 4 \sqrt{7}$

<u>Question</u> : 9

$x = - 1$
$y = - 3$

<u>Question</u> : 11

LHS isn't equal to RHS

<u>Question</u> : 12

$x = \dfrac{ \sqrt{3} }{2 \sqrt{2} }$

Solution is in attachment ~

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3. A sign company is building a sign with the dimensions shown. What is the area, in square feet, of the sign? Round to the near

Aleks04 [339]

Answer:

84.87sq ft

Step-by-step explanation:

Let ABC be the triangle and AD be the perpendicular on BC such that BD=DC=7ft.

Now, it is known that $\frac{DC}{AC}=cos60^{0}$

$AC=\frac{7}{\frac{1}{2}}$

$AC=7ft$

Now, in triangle ADC, we have

$(AC)^{2}=(AD)^{2}+(DC)^{2}$

$(14)^{2}=(AD)^{2}+(7)^{2}$

$196-49=(AD)^{2}$

$AD=12.12ft$

Now, area of the triangle= $\frac{1}{2}{\times}b{\times}h$

= $\frac{1}{2}{\times}14{\times}12.12$

= $84.87sq ft$

Thus, area of the building is 84.87sq ft.

8 0

2 years ago

Can someone pls help me quickly

nydimaria [60]

Answer:

B AND F

Step-by-step explanation:

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2 years ago

Someone please help out?

Delvig [45]

I dont know im trying to figure that out

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3 years ago

Forty discrete math students are to be divided into eight discussion groups, each consisting of five students. In how many ways

VARVARA [1.3K]

Answer:

Step-by-step explanation:

Given data

the number of students n=40

the number of groups r= 8

We are going to use the combination approach to solve the problem

nCr= n!/r!(n-r)!

substituting into the expression for the number of ways we have

40C8= 40!/8!(40-8)!

nCr= 40!/8!(32)!

nCr= 40*39*38*37*36*35*34*33*32!/8!(32)!

nCr= 40*39*38*37*36*35*34*33*/8!

nCr= 40*39*38*37*36*35*34*33*/8*7*6*5*4*3*2

nCr= 3100796899200/40320

nCr=76904685 ways

4 0

3 years ago

Which table contains only points that lie on the line of the equation y = 6x - 6?

Fittoniya [83]

Answer:

The answer is G

Step-by-step explanation:

2 x 6 = 12

12 - 6 = 6

_________

-2 x 6 = -12

-12 - 6 = (-18)

7 0

3 years ago

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Help me i really need this .no spam​

Help me i really need this .no spam