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Harman [31]
3 years ago
14

Suppose that y varies jointly with w and x and inversely with z and y = 32- when w = 6, x = 20, and z = 3. Write the equation th

at models the relationship
Mathematics
1 answer:
natulia [17]3 years ago
3 0
Y directly proportional to WX  and inversely to Z. 

Y=k(WX)/Z
Where k is the constant of proportionality. 
So, the first thing is to find the value of this constant. 

k = YZ/WX
  = (32×3)/(6×20)
  = 96/120
  = 0.8
The <span>equation that models the relationship will be;
Y = 0.8(WX/Z)</span>
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Phoenix [80]

Answer:

Since i don't know what formula is mentioned. I just used the easiest way to solve :)

Step-by-step explanation:

(3x^2 + 3)^3 = (3x^2)^3 + 3^3 + 3((3x^2)^2)(3) + 3(3x^2)(3^2)

              = 27x^6 + 27 + 3(9x^4 \times 3) + 3(3x^2 \times 9)\\\\=27x^6 + 27 + 81x^4 + 81x^2\\\\=27x^6  + 81x^4 + 81x^2 + 27\\\\

\int\limits {(3x^2+3)^3} \, dx  = \int\limits {27x^6 + 81x^4+81x^2 + 27} \, dx

                      = \frac{27}{7}x^7 + \frac{81}{5}x^5+\frac{81}{3}x^3 + 27x +C\\\\= \frac{27}{7}x^7 + \frac{81}{5}x^5+27x^3 + 27x +C\\\\

8 0
3 years ago
Dilate point a in relation to the origin by a dilation factor of 5.?
IRINA_888 [86]

Answer:

origin dilation if 5. is 5

7 0
2 years ago
What is the volume of the figure?
anzhelika [568]
8 x 2 x 3 is the volume
5 0
3 years ago
Read 2 more answers
An equation of the line that passes through the given point and is parallel to the graph of the given equation
notsponge [240]

To construct the equations for these lines, we are going to use the point-slope formula, which is:

(y - y_1) = m(x - x_1)

  • m is the slope of the line
  • (x_1, y_1) is a point on the line

1)

In this case, our point is (2, -1) and our line has a slope of 5. (Remember that the line is parallel, meaning that it has the same slope as the given line. Since the line is in the y = mx + b format, we could easily pick out the slope m as being 5.)

Thus, we can "plug in" what we know into our formula to find the equation of our line:

(y + 1) = 5(x - 2)

(y + 1) = 5x - 10

y = 5x - 11


2)

We are going to do the same thing, except our point is now (0, -5) and our slope is now 9.

(y + 5) = 9(x - 0)

y = 9x - 5


Our equations are:

1) y = 5x - 11

2) y = 9x - 5

7 0
2 years ago
Rationalize the denominator of the following expression and simplify:
Mama L [17]
To "rationalize the denominator" is another way to say, getting rid of that pesky radical at the bottom.

we'll simply start by multiplying top and bottom by the "conjugate" of the denominator, recall difference of squares, anyhow, let's do so

\bf \cfrac{6+\sqrt{2}}{5-\sqrt{2}}\cdot \cfrac{5+\sqrt{2}}{5+\sqrt{2}}\implies \cfrac{(6+\sqrt{2})(5+\sqrt{2})}{(5-\sqrt{2})(5+\sqrt{2})}\implies \cfrac{(6+\sqrt{2})(5+\sqrt{2})}{5^2-(\sqrt{2})^2}&#10;\\\\\\&#10;\cfrac{30+6\sqrt{2}+5\sqrt{2}+(\sqrt{2})^2}{25-2}\implies \cfrac{30+11\sqrt{2}+2}{23}\implies \cfrac{32+11\sqrt{2}}{23}
4 0
3 years ago
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