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2 years ago

Help me on this math question please

Mathematics

1 answer:

Debora [2.8K]2 years ago

3 0

Answer:

its answer is 20

Step-by-step explanation:

as we know,

a=5

b=4

c=7

now,

3(b+a)-c

= 3(4+5)-7(here,putting the value of a,b&c)

=3×9-7

=27-7

=20.

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Find all complex solutions of 7x^2-7x+3=0

Sedaia [141]

Answer:

The complex solutions are

$x = (\frac{7-\sqrt{35} i }{42} , ) x = \frac{7 + \sqrt{35} i }{42})$

Step-by-step explanation:

Step(i):-

Given equation 7 x² - 7 x +3=0

$x = (\frac{-b -\sqrt{b^{2}-4ac } }{2ac} , \frac{-b +\sqrt{b^{2}-4ac } }{2ac})$

Given standard equation

a x² +b x +c =0

a = 7 , b= -7 and c=3

Step(ii):-

$x = (\frac{-(-7) -\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)} , \frac{-(-7) +\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)})$

$x = (\frac{7-\sqrt{(49-84 } }{42} , \frac{7 +\sqrt{(49-84 } }{42})$

$x = (\frac{7-\sqrt{35i^{2} } }{42} , \frac{7 + \sqrt{35i^{2} } }{42})$

$x = (\frac{7-\sqrt{35} i }{42} , \frac{7 + \sqrt{35} i }{42})$

8 0

2 years ago

Find measure jk Answers are 52, 128, 154 & 180

Mamont248 [21]

Answer:

b. 128°

Step-by-step explanation:

arc LJ = 2 (26) = 52°

arc KL = 180° (half circle)

arc JK = 360° - (arc LJ + arc KL)

arc JK = 360° - 232°

arc JK = 128°

Answer

b. 128°

8 0

3 years ago

The assembly line that produces an electronic component of a missile system has historically resulted in a 2% defectiverate. a r

sattari [20]

Defective rate can be expected to keep an eye on a Poisson distribution. Mean is equal to 800(0.02) = 16, Variance is 16, and so standard deviation is 4.
X = 800(0.04) = 32, Using normal approximation of the Poisson distribution Z1 = (32-16)/4 = 4.
P(greater than 4%) = P(Z>4) = 1 – 0.999968 = 0.000032, which implies that having such a defective rate is extremely unlikely.

If the defective rate in the random sample is 4 percent then it is very likely that the assembly line produces more than 2% defective rate now.

3 0

2 years ago

HELP ME PLEEEAASSEEE I SUCK AT MATH

irakobra [83]

Answer:

the answer is letter d

5 0

2 years ago

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Ber [7]