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weeeeeb [17]
3 years ago
13

Please help me! I am struggling

Mathematics
1 answer:
Ket [755]3 years ago
3 0
X =80 its a simple problem
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Helpppppppp pleaseeee!!!!!!!!
SashulF [63]

Answer:

29.5 square inches

Step-by-step explanation:

Let's divide the shape into 3 parts to make it easy for us to find the area.

- a wide triangle

- a triangle

- a shorter rectangle

For the wider rectangle, the area is;

A1 = 8 × 2 = 16 in²

For the triangle, the area is;

A2 = ½(7 - 2) × 3

A2 = 7.5 in²

For the shorter rectangle, the area is;

A3 = 3 × 2

A3 = 6 in²

Total area = A1 + A2 + A3 = 16 + 7.5 + 6 = 29.5 square inches

8 0
3 years ago
Answer to question one pleaseeeee help !!
Salsk061 [2.6K]
The answer is 19.6 cm^2


you should find the height of the triangle by heron formula: it will be 9.8

so the area is
(9.8 \times 4 ) \div 2= 39.2 \div 2 = 19.6



good luck
8 0
3 years ago
Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)
kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios  between two points (x1,f(x1)) and (x2,f(x2)) is

  • ARC = [f(x2)-f(x1)]/ (x2-x1)

<em>In case a)</em>

f(-1)= -5*(-1)-8=5-8= -3          f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

<em>In case b)</em>

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

<em>In case c)</em>

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0
3 years ago
Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

5 0
3 years ago
Determine two coterminal angles (one positive and one negative) for the angle - 361".​
ololo11 [35]
The answer is minus 666 that’s the answer byee
7 0
3 years ago
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