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Sveta_85 [38]
3 years ago
10

ABCDEF - QRSTUV. Find the length of ST.

Mathematics
1 answer:
labwork [276]3 years ago
6 0

Answer:

Option (1)

Step-by-step explanation:

It's given in the question, ABCDEF ~ QRSTUV,

Their corresponding sides will be proportional.

\frac{AB}{QR}= \frac{BC}{RS}= \frac{CD}{ST}= \frac{DE}{TU}= \frac{EF}{UV}

Now we choose \frac{DE}{TU}=\frac{CD}{ST}

From the figure attached,

\frac{6}{2.4}=\frac{5.4}{ST}

ST = \frac{5.4\times 2.4}{6}

ST = 2.16

Therefore, Option (1) is the correct option.

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What are square numbers
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Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

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t = 4 (three)

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n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

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Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

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Therefore, the total probability of drawing an ace, a three and then a jack is:

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4 0
3 years ago
Ursula and Andre competed against each other in a swimming race. Ursula swam at a rate of 60 meters per minute and Andre swam at
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Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
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the two swimmers met at a distance of:
12×1
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6 0
3 years ago
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