Answer:
Sample range appears to be a biased estimator since it consistently underestimated the population range.
Step-by-step explanation:
The calculation of sample range appear to be a biased or unbiased estimator of population range is shown below:-
Sample range (x) Frequency (f) fx
9 1 9
14 1 14
15 2 30
16 1 16
17 4 68
18 2 36
19 1 19
20 3 60
21 5 105
22 2 44
23 1 23
24 2 48
25 4 100
26 4 104
27 2 54
28 4 112
29 3 87
30 1 30
31 5 155
32 2 64
Total 50 1,178
Mean sample range = ∑ fx ÷ ∑ f
= 1,178 ÷ 50
= 23.56
Therefore the sample range is not equal to population range that is
23.56 ≠ 32
Thus, Sample range appears to be biased estimator.
So, the correct option is A.
Answer:
B) an = 3 + 2(n-1)
Step-by-step explanation:
just plugging in the values :))
hope i helped :)
57-8=49
So then 7y=49
Y=1 so 2y=2