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Mila [183]
3 years ago
8

Answer all !!!!!!!!!! Help please ASAP!!!!!!!!!!! 20 points

Mathematics
1 answer:
eimsori [14]3 years ago
8 0
I know 15, 17, 18, and 19 are for sure true and that 16 is false. I’m not sure about 20
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Work out the size of angle x.<br>X<br>140°<br>105°​
yKpoI14uk [10]

Answer:

- 65

Step-by-step explanation:

x + 140 + 105 = 180

x + 245 = 180

x = 180- 245 = - 65

3 0
3 years ago
BRAINLIEST !!! Can someone add me as a friend plz need to look someone up but cant till someone adds me
eimsori [14]

Answer:

I have done what you want

4 0
2 years ago
Read 2 more answers
A rectangular parking lot has a perimeter of 232 feet. the length of the parking lot is 36 feet less then the width. find the le
Troyanec [42]

Answer:

Length: 40  Width: 76

Step-by-step explanation:

W is width, and L is length.

We know that the length is 36 less than the width, so L = w - 36.  Two times the width plus two times the length equals the perimeter, so set up the equation for the perimeter as:

232 = 2w + 2(w-36)

Now solve for w:

232 = 2w + 2w - 72

304 = 4w

w = 76

we now know that the width is 76, so solve for the length:

L= 76-36

L = 40

7 0
3 years ago
A discount store takes 50% off of the retail price of a desk. For the store's holiday sale, it takes an additional 20% off of al
Serhud [2]

We are given the retail price of desk as $320. The store takes 50% off of the retail price of desk, then its price would become half of the original.

So its new price would be $160.

Now it says that it takes an additional 20% off of all furniture on store's holiday sale. So we need to cut off 20% from new price $160.

Holiday discount = 20% of $160 = 0.2 × 160 = 32.

Final selling price would be = $160 - $32 = $128.

So $128 is the final answer.

3 0
3 years ago
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Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3
AlexFokin [52]
The ODE is separable, i.e. you can write

\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx

Integrating both sides gives the general solution.

\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx
y=-\ln|\cos x|+C

Given that y\left(\dfrac\pi4\right)=3, we have

3=-\ln\left|\cos\dfrac\pi4\right|+C
3=-\ln\dfrac1{\sqrt2}+C
3-\ln\sqrt2=C


and so the particular solution to the IVP is

y=-\ln|\cos x|+3-\ln\sqrt2
y=3-\ln|\sqrt2\cos x|
4 0
3 years ago
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