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2 years ago

Find x in this picture pls

Mathematics

2 answers:

jolli1 [7]2 years ago

8 0

X=68 because its vertical

blondinia [14]2 years ago

3 0

Answer:

X=62

Step-by-step explanation:

solve half of it like 90 degrees +22 degrees. then minus from 180 degrees

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How would I solve this?? 5p-8(p+1)>16

alexandr402 [8]

*To solve inequalities is similar to solving equations: isolate the desired variable to one side.

So firstly, distribute -8 to (p + 1):

$5p-8p-8>16$

Next, combine like terms:

$-3p-8>16$

Next, add 8 to both sides:

$-3p>24$

Lastly, divide both sides by -3. Now since you are dividing by a negative, you will be flipping the inequality symbol as well. Your final answer will be $p$

6 0

3 years ago

Solve equation by using the quadratic formula.

adoni [48]

ANSWER IS C because I looked it up

3 0

3 years ago

Oliver is buying his new soccer uniform his jersey was $21.50 his cleats for $44.95 and his water bottle was $12 if you paid wit

Anon25 [30]

Answer:

$21.55

Step-by-step explanation:

21.50 + 44.95 + 12 = $78.45

100 - 78.45= $21.55

8 0

3 years ago

Read 2 more answers

I need help fast! This is polynomials help

antiseptic1488 [7]

Answer:

incorrect
correct
incorrect

Step-by-step explanation:

A + B = (-4x^2 +2x -5) +(3x^2 +6) = x^2(-4+3) +x(2) +(-5+6) = -x^2 +2x +1

The given sum is Incorrect.

A - C = (-4x^2 +2x -5) -(-5x -4) = -4x^2 +x(2+5) +(-5+4) = -4x^2 +7x -1

The given difference is Correct.

B + C = (3x^2 +6) +(-5x -4) = 3x^2 -6x +2

The given sum is Incorrect.

5 0

3 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago