Question

Have to find the area of the figure please help!

Answer 1

Answer:   Area = $60\sqrt{2}$

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Explanation:

The triangle on the right side is a 45-45-90 triangle

The hypotenuse is 8, so the leg length is $\frac{8}{\sqrt{2}} = \frac{8\sqrt{2}}{2} = 4\sqrt{2}$

This is the height of the parallelogram. The base is 15 which is always perpendicular to the height, and vice versa.

The area of this parallelogram is therefore, $\text{base*height} = 15*4\sqrt{2} = 60\sqrt{2}$