<h3>
Answer: Yes they are equivalent</h3>
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Work Shown:
Expand out the first expression to get
(a-3)(2a^2 + 3a + 3)
a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)
2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9
2a^3 + (3a^2-6a^2) + (3a-9a) - 9
2a^3 - 3a^2 - 6a - 9
Divide every term by 2 so we can pull out a 2 through the distributive property
2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)
This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
Factors are the numbers you multiply together to get another number. When you find the factors of two or more numbers, and then find some factors are the same ("common"), then they are the "common factors<span>"
</span>Example: 12 and 30
• The factors of 12 are: 1, 2, 3, 4, 6 and 12
• The factors of 30 are: 1, 2, 3, 5, 6, 10, 15 and 30
<span>So the common factors of 12 and 30 are: 1, 2, 3 and 6
</span>
-Hope this helped.
Answer:
(a) 
Step-by-step explanation:
Given
Required
Determine the time in each lap
The unit time in each lap is calculated by dividing the total time by the number of laps; i.e.;
Substitute values for Time and Lap
Answer:
≈100.5
Step-by-step explanation:
hope this helps
