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3 years ago

7

PLEASE HELP, WILL MARK BRAINLIEST !!!

2 answers:

shutvik [7]3 years ago

6 0

Answer:

- 2

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ - 4, 3 ] , then

f(b) = f(3) = 3² - 3 - 8 = 9 - 3 - 8 = - 2

f(a) = f(- 4) = (- 4)² - (- 4) - 8 = 16 + 4 - 8 = 12 , tus

average rate of change = $\frac{-2-12}{3-(-4)}$ = $\frac{-14}{7}$ = - 2

Bezzdna [24]3 years ago

6 0

Answer is -2 have a nice day!

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By which smallast number must the following number be divided so that the quotient is a perfect cube

jenyasd209 [6]

Answer:

60

Step-by-step explanation:

8640/60 is 144. 144 is a perfect square. 12*12 is 144

8 0

3 years ago

Read 2 more answers

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

The average of 6 ages men is 35 years and the average of four of them is 32. Find the ages of the remaining two men if one is 3

prisoha [69]

Answer:

the first one must be 39.5 and the other 42.5

Step-by-step explanation:

multiply 35 by 6 and subtract 32 x 4 you are left with 82. Divide that by 2 and make the difference 3.

6 0

3 years ago

A local gym offers a trial membership for 3 months. It discounts the regular monthly fee x by $25. If the total cost of the tria

adoni [48]

X-25 < 100

x minus the $25 discount has to be less than 100

7 0

3 years ago

Read 2 more answers

A student says that the graph of the equation y = 3(x + 8) is the same as the graph of y = 3x, only translated upwards by 8 unit

Wittaler [7]

Given:

A student says that the graph of the equation $y = 3(x + 8)$ is the same as the graph of $y = 3x$ , only translated upwards by 8 units.

To find:

Whether the student is correct or not.

Solution:

Initial equation is

$y=3x$

$f(x)=3x$

Equation of after transformation is

$y=3(x+8)$

$g(x)=3(x+8)$

Now,

$g(x)=f(x+8)$ ...(i)

The translation is defined as

$g(x)=f(x+a)+b$ ...(ii)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

From (i) and (ii), we get

$a=8\text{ and }b=0$

Therefore, the graph of $y=3x$ translated left by 8 units. Hence, the student is wrong.

8 0

3 years ago