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elena-14-01-66 [18.8K]
2 years ago
7

What is the lateral area of this regular octagonal pyramid?

Mathematics
2 answers:
Murrr4er [49]2 years ago
8 0

Answer:

229.7

Step-by-step explanation:

8 * 1/2 * 5.8 * 7 * sqrt(2.)

Aleksandr [31]2 years ago
8 0

The answer is 229.7 cm²

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Subtract. Write the difference in simplest form.<br><br>(5n - 3) - (-2n + 7)​
kolezko [41]

Answer:

Simplifying

(5n + -3) + -1(-2n + 7) = 0

Reorder the terms:

(-3 + 5n) + -1(-2n + 7) = 0

Remove parenthesis around (-3 + 5n)

-3 + 5n + -1(-2n + 7) = 0

Reorder the terms:

-3 + 5n + -1(7 + -2n) = 0

-3 + 5n + (7 * -1 + -2n * -1) = 0

-3 + 5n + (-7 + 2n) = 0

Reorder the terms:

-3 + -7 + 5n + 2n = 0

Combine like terms: -3 + -7 = -10

-10 + 5n + 2n = 0

Combine like terms: 5n + 2n = 7n

-10 + 7n = 0

Solving

-10 + 7n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + 7n = 0 + 10

Combine like terms: -10 + 10 = 0

0 + 7n = 0 + 10

7n = 0 + 10

Combine like terms: 0 + 10 = 10

7n = 10

Divide each side by '7'.

n = 1.428571429

Simplifying

n = 1.428571429

3 0
3 years ago
PLEASE HELP ME I DONT WANT TO FAIL
Ksenya-84 [330]

Answer:

294

Step-by-step explanation:

6 0
3 years ago
Which function represents the sequence -5.5, -4.75 -4,-3.25... ?​
kumpel [21]
The answer I think should be
C main
3 0
2 years ago
Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards.  This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

3 0
2 years ago
Read 2 more answers
Straight forward questions I just don't know how to do them.
OLga [1]
Answer:

_____________________________

3 0
2 years ago
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