Answer:
The volume of the larger solid is 
Step-by-step explanation:
<u><em>The question is</em></u>
If these solids are similar, find the volume of the larger solid
step 1
Find the scale factor
we know that
If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
Let
x ----> the height of the larger solid in mm
y ----> the height of the smaller solid in mm
z ---> the scale factor
we have
substitute
---> scale factor
step 2
Find the volume of the larger solid
we know that
If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
x ----> the volume of the larger solid in cubic millimeters
y ----> the volume of the smaller solid in in cubic millimeters
z ---> the scale factor
we have
substitute the values
solve for x
In the pool, the rail of the table can be considered a rebound line as the definition suggest the table's rail can be used as a rebound line.
<h3>What is a rebound line?</h3>
Water is released from the earth when it is squeezed or compacted by some force. As a further stage, the stress in the soil is removed, allowing the soil sample to expand back to its original size.
The soil will try to reclaim some of the stress it has lost after the stress has been released. Rebound is the word for this procedure.
We have a statement:
The rail of the table can be considered which of the following when making a bank shot:
The answer is a rebound line.
As the definition of the rebound line, the table's rail can be used as a rebound line.
Thus, in the pool, the rail of the table can be considered a rebound line as the definition suggest the table's rail can be used as a rebound line.
Learn more about the rebound line here:
brainly.com/question/15504221
SPJ1
Answer:
Please check the explanation.
Step-by-step explanation:
<u>Calculating the area of the outer rectangle:</u>
Given
- The length outer rectangle = l = 3x - 1
- The width of outer rectangle = w = 5x + 2
Thus,
The area of the outer rectangle:
<u>Calculating the area of the inner rectangle:</u>
Given
- The length inner rectangle = l = x + 7
- The width of inner rectangle = w = x
Thus,
The area of the outer rectangle:
A = wl
= x(x+7)
= x² + 7
<u>Calculating the area of the shaded region:</u>
As
The area of the outer rectangle = 15x² + x - 2
The area of the inner rectangle = x² + 7
- The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.
Thus,
shaded region Area = Outer Rectangle Area - Inner Rectangle Area
= 15x² + x - 2 - (x² + 7)
= 15x² + x - 2 - x² - 7
= 14x² + x - 9
Therefore, the Area of the shaded region is: 14x² + x - 9
C 4and 12 are the factors of 48
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
