The number of that grow sugar beet =12
2 answers:
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Answer:
(x) =
Step-by-step explanation:
let y = f(x), then rearrange making x the subject
y = x + 4 ( subtract 4 from both sides )
y - 4 = x ( multiply both sides by 5 to clear the fraction )
5y - 20 = x
Change y back into terms of x with x = (x) , then
(x) = 5x - 20
<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3
</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y
Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2
Divide that out and we get
</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y
Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2
Divide that out and we get