The answer i got was c because the letter x goes into each of them because they each have a x in them. It would be B but 3 doesnt go into 28.
Basically it's d because they are all alive hypothetically
Answer:
The number of distinct arrangements is <em>12600</em><em>.</em>
Step-by-step explanation:
This is a permutation type of question and therefore the number of distinguishable permutations is:
n!/(n₁! n₂! n₃! ... nₓ!)
where
- n₁, n₂, n₃ ... is the number of arrangements for each object
- n is the number of objects
- nₓ is the number of arrangements for the last object
In this case
- n₁ is the identical copies of Hamlet
- n₂ is the identical copies of Macbeth
- n₃ is the identical copies of Romeo and Juliet
- nₓ = n₄ is the one copy of Midsummer's Night Dream
Therefore,
<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>
<em> = </em><em>12600 ways</em>
<em />
Thus, the number of distinct arrangements is <em>12600</em><em>.</em>
Answer:
total animal 40
number of bears are 40×3/8=15
number of dogs will be 40 - 15 = 35
Step-by-step explanation:
hope it helped u buddy
There are 4 choose 3 ways to hold 3 kings and 4 possible queens to make up the fourth card of the hand out of a total of 54 choose 4 possible four-card hands, which gives us the following expression for the probability of being dealt 3 kings and a queen out of 4 cards: Or roughly 1 in every 16920 four card hands.
