Solving for x
Since x<span> is on the right hand side of the </span>equation<span> switch the sides so it is on the left hand side of the </span>equation<span>.
</span><span>2x+yi=−14−3i
</span>
Since <span>yi</span><span> does not contain the </span>variable<span> to solve for move it to the right-hand side of the </span>equation<span> by subtracting </span><span>yi</span><span> from both sides.
</span><span>2x=−yi−14−3i
</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>2.
</span><span>x=−<span><span>yi/</span>2</span>−7−<span><span>3i/</span>2
Solving for y
</span></span>Since y<span> is on the right hand side of the </span>equation<span> switch the sides so it is on the left hand side of the </span>equation<span>.
</span><span>2x+yi=−14−3i
</span>Since <span>2x</span><span> does not contain the </span>variable<span> to solve for move it to the right hand side of the </span>equation<span> by subtracting </span><span>2x</span><span> from both sides.
</span><span>yi=−2x−14−3i
</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>i.
</span><span>y=2xi+14i−3
</span>x=−yi/2−7−3i/2
y=2xi+14i−3
Negative dividing by negative gives positive,
so 18:9=2
<span> If all numbers are greater than zero and no repeated numbers exist these are the 5 possible combinations:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6
2 + 3 + 6
2 + 4 + 5.
If one number is allowed to be zero and no repeated numbers exist these are 5 combinations:
</span><span> 0 + 11
1 + 1 + 9
2 + 2 + 7
3 + 3 + 5
4 + 4 + 3
5 + 5 + 1
</span><span>
Hope this helps
</span>
To get 4% of 800 you times 800 by 4 and divide it by 100. Once you have that amount you add it to 800 to find the amount you will have in your bank the first year.
To get the next year's amount you then get 4% of 832(because after the first year you have more than $800) and then add the 4% to 832, that is the answer for the second year.
To find the third year's amount you get 4% of the new amount (last year's total) and add it to last year's total, that is your total for the third year.
So the first year will be:
(800x4÷100)+800
=32+800
=832
The second year will be:
832+(832x4÷100)
=832+33.28
=865.28
The third year will be:
(865.28×4÷100)+865.28
=34.61(rounded off)+865.28
=899.89
Answer:
C) 119.75 + 2.25p <= 500; p <= 169
Step-by-step explanation:
My friend, for this problem you must realize that there is a fixed cost of 119.75 that we add always. Then $2.25 per pastry manufactured is also part of the total costs. Thus, we add both of them where p represents pastry to get 119.75 + 2.25p.
But, the question says the shopkeeper would like to stay under or be exactly at $500 for total costs. Thus, for this inequality, we set this equation as being <u>less than equal to 500.</u>
<u />
Solve for p by adding 119.75 on both side and dividing both sides by 2.25 afterwards and you get 169.
