These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Answer:
y=1/12x+1
Step-by-step explanation:
For an equation to be perpendicular everything but the slope will remain the same. To find the slope of equation d switch the sign and take the reciprocal of the slope of line c. Line c gives a slope of -12/1 so the slope for line d will be positive 1/12 and keep everything else the same when creating your equation.
Answer:
19
Step-by-step explanation:
whenever a number is behind a variable (letter) its always a co efficient.
Let p and w represent the speed of the plane and the speed of the wind, respectively.
.. speed = distance/time
.. p +w = 720/3 = 240
.. p -w = 720/4 = 180
Add the two equations to eliminate w.
.. 2p = 420
.. p = 210
.. w = p -180 = 30
The speed of the wind is 30 mph.
The speed of the plane in still air is 210 mph.
Answer:
It is A (2714.34 not rounded)
Step-by-step explanation:
Volume = πr2h= π×122×6= 864π= 2714.3360527016 meters3
