Answer:
a) Probability of picking Two MAGA buttons without replacement = 0.15
b) Probability of picking a MAGA and GND button in that order = 0.0833
Probability of picking a MAGA and GND button in with the order unimportant = 0.167
Step-by-step explanation:
10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL] buttons.
Total number of buttons = 10 + 5 + 10 = 25
Let probability of picking a MAGA button be P(M) = 10/25 = 0.4
Probability of picking a GND button be P(G) = 5/25 = 0.2
Probability of picking a NAW button be P(N) = 10/25 = 0.4
a) Probability of picking Two MAGA buttons without replacement = (10/25) × (9/24) = 3/20 = 0.15
b) Probability of picking a MAGA and GND button in that order = (10/25) × (5/24) = 1/12 = 0.0833
Probability of picking a MAGA and GND button in with the order unimportant = [(10/25) × (5/24)] + [(5/25) × (10/24)] = 1/6 = 0.167
100%/x%=27.5/17.16
(100/x)*x=(27.5/17.16)*x
100=1.60256410256*x divide both sides of the equation by (1.60256410256) to get x
100/1.60256410256=x
62.4=x
x=62.4
So first, you get the absolute value to one side:

Next, set up two equations; One where the value inside the absolute value lines is positive, and another where it is negative, and solve both for the variable:

Your answers are
8 and -8, or +-8.
There are 9 positive integers with 1 digit (1 - 9).
There are 90 integers with 2 digits (10 - 99).
There are 900 integers with 3 digits (100 - 999).
There are 9000 integers with 4 digits (1000 - 9999).
And so on. It stands to reason that there are
integers with
digits.
Now,
1000 = 9 + 900 + 91
so the 1000th positive integer with an odd number of digits is the 91th number with 3 digits, which is 190.
C is the answer to your problem have a good day