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3 years ago

PLZ HELP Sorry it’s not a lot of points I don’t have that many

Mathematics

1 answer:

Snezhnost [94]3 years ago

5 0

1. Census = D.
2.Sample = A.
3.Survey = E.
4. Population = B.
5. Inferences = C.

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What expression is equivalent to (^3√2^5)^1/4

Nezavi [6.7K]

Soo first apply the exponent rule (2^5)^1/3*1/4
1/3*1/4= 1/12
so (2^5)^1/12
then you apply the exponent rule again 2^5*1/2
so 5*1/12= 5/12
So the answer would be 2^5/12

6 0

4 years ago

Read 2 more answers

A right angled triangle has two shorter sides and one is twice as long as the other. The hypotenuse is 25cm long. What are the l

Bas_tet [7]

Answer: x = 14.43

Step-by-step explanation:

The Pythagorean Theorem states the following:

a^2 + b^2 = c^2

Make one side of the triangle x

Make the second side of the triangle 2x

Now, you can plug the values into the equation, right?

x^2 + 2x^2 = 25^2 or 625

3x^2 = 625

Divide each side by 3 and you are left with:

x^2 = 208.33

Now, take the square root of 208.33

x = 14.43

That is the shorter side. The longer side is twice that value: Therefore, 14.43 x 2 = 28.86 14.43 is one side of the triangle. The other is that same value times two. Therefore, the sides of your triangle are: 14.43 Shorter side 28.86 Longer side

5 0

3 years ago

Read 2 more answers

Are 27 49 57 63 composite numbers

Helen [10]

Yes they are
Composite numbers <span />

7 0

3 years ago

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Consider the following hypothesis test: H0: μ1 - μ2 = 0 Ha: μ1 - μ2 ≠ 0 There are two independent samples taken from the two pop

nlexa [21]

Answer:

The value of the test statistic is $z = 1.78$

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

$\mu_1 = 110, s_1 = \frac{7.2}{\sqrt{81}} = 0.8$

Sample 2:

$\mu_2 = 108, s_2 = \frac{6.3}{\sqrt{64}} = 0.7875$

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

Distribution of the difference:

$X = \mu_1 - \mu_2 = 110 - 108 = 2$

$s = \sqrt{s_1^2+s_2^2} = \sqrt{0.8^2+0.7875^2} = 1.1226$

What is the value of the test statistic?

$z = \frac{X - \mu}{s}$

$z = \frac{2 - 0}{1.1226}$

$z = 1.78$

The value of the test statistic is $z = 1.78$

5 0

3 years ago

The low temperatures for 5 days was 5, -2, -11 ,0 and-3.What was the average low temperature for those days

Daniel [21]

Data:
Average (A): ?
Arithmetic mean (A.M) = 5, -2, -11, 0, -3sum of n numbers = 5

Solving:
$A = \frac{AM}{n} = \frac{5+(-2)+(-11)+0+(-3)}{5} = \frac{5-2-11-3}{5} = \frac{\diagup\!\!\!\!3-11-\diagup\!\!\!\!3}{5} = \frac{-11}{5} = - 2.2$

Answer:

<span>The average low temperature of these days is -2.2</span>

3 0

3 years ago