Answer:
The explicit rule is:
Step-by-step explanation:
The explicit rule is given by:
The given sequence is 25,21,17,13
d=21-25
d=-4
We plug in the values into the formula to get;
At what position on the number line is the red dot located?
1 answer:
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Answer:
hello your question is incomplete attached below is a the complete question
answer : n = 5
Step-by-step explanation:
lets consider N to be 5
To prove that the least number 'n' = 5
we will represent this information in a graph as vertex
Black edge = Friends
Blue edge = not Friends
From the attached diagram any vertex contains 0,1,2,3,4 black lines and 4,3,2,1,0 blue lines
attached below is an explanation related to the choice of n = 5
considering n = 5 is satisfied by the explanation given
It's easy once you spot the ones that can cross cancel!
Say we have the fractions 8/10 and 20/23. (it's easier to see on top of each other)
If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.
This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.
Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.
Hope I helped!
Answer:
a) zeros of the function are x = 1 and, x = -1
b) zeros of the function are x = 2 and, x = 4
c) zeros of the function are x =
d) zeros of the function are x = and, x = 17
Step-by-step explanation:
Zeros of the function are the values of the variable that will lead to the result of the equation being zero.
Thus,
a) f(x)= (x +1)(x − 1)(x² +1)
now,
for the (x +1)(x − 1)(x² +1) = 0
the condition that must be followed is
(x +1) = 0 ..........(1)
or
(x − 1) = 0 ..........(2)
or
(x² +1) = 0 ...........(3)
considering the equation 1, we have
(x +1) = 0
or
x = -1
for
(x − 1) = 0
x = 1
and,
for (x² +1) = 0
or
x² = -1
or
x = √(-1) (neglected as it is a imaginary root)
Thus,
zeros of the function are x = 1 and, x = -1
b) g(x) = (x − 4)³(x − 2)⁸
now,
for the (x − 4)³(x − 2)⁸ = 0
the condition that must be followed is
(x − 4)³ = 0 ..........(1)
or
(x − 2)⁸ = 0 ..........(2)
considering the equation 1, we have
(x − 4)³ = 0
or
x -4 = 0
or
x = 4
and,
for (x − 2)⁸ = 0
or
x - 2 = 0
or
x = 2
Thus,
zeros of the function are x = 2 and, x = 4
c) h(x) = (2x − 3)⁵
now,
for the (2x − 3)⁵ = 0
the condition that must be followed is
(2x − 3)⁵ = 0
or
2x - 3 = 0
or
2x = 3
or
x =
Thus,
zeros of the function are x =
d) k(x) =(3x +4)¹⁰⁰(x − 17)⁴
now,
for the (3x +4)¹⁰⁰(x − 17)⁴ = 0
the condition that must be followed is
(3x +4)¹⁰⁰ = 0 ..........(1)
or
(x − 17)⁴ = 0 ..........(2)
considering the equation 1, we have
(3x +4)¹⁰⁰ = 0
or
(3x +4) = 0
or
3x = -4
or
x =
and,
for (x − 17)⁴ = 0
or
x - 17 = 0
or
x = 17
Thus,
zeros of the function are x = and, x = 17