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MariettaO [177]
3 years ago
13

Wendy wants to put a wallpaper border around her bedroom. The room has two walls that each measure 10 feet 5

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

11 yards

Step-by-step explanation:

The room has two sides both measuring 10 feet 5 inches. This gives a total of 20 feet 10 inches. It also has the other two sides both measuring 6 feet 1 inch and that too gives a total of 12 feet 2 inches. Adding them all together results in 32 feet 12 inches. Better still, the perimeter of the room is derived as;

Perimeter = 2 (L + W)

Perimeter = 2 (10'5" + 6'1")

Perimeter = 2(16'6")

Perimeter = 32'12"

Having in mind our conversion rate of 12 inches equals 1 foot, the results can be properly expressed as 32 feet plus 1 foot which gives us 33 feet.

If the perimeter of Wendy's room is now given as 33 feet, the conversion rate between feet and yards can now be applied. Having been given that

3 feet = 1 yard

Then 1 yard = 3 feet/3, that is

y = 3/3

Hence,

y = 33/3

y = 11

The results show that Wendy would needs to buy a total of 11 yards of wallpaper border.

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murzikaleks [220]
So here we're dealing with equivalent fractions.
It's really simple to find the answer, so I'll try to explain the best I can.

2 dogs / 5 cats is really just 2/5.
If we want to find an equivalent fraction, we have to multiply the numerator and the denominator by the same number.

Currently the number of cats is 5, and we need it to be 140. What we need to do is find the number it has to be multiplied by to equal 140, which is 140 divided by 5. 140 divided by 5 is 28, so 5 x 28 = 140!

We need to multiply the denominator (5) by 28, so that we can get 140. What we have now is ?/140.

Like I said, to find an equivalent fraction, we need to multiply the numerator by the same number as we did the denominator, which is 28!

2 x 28 = 56.

So 2/5 is the same as 56/140.

The answer is D) 56 Dogs/140 Cats.

Hope this helps!
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3 years ago
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three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

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1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

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