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3 years ago

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27.5 a rational number solve it

1 answer:

JulijaS [17]3 years ago

6 0

The only irrational numbers are the ones with a square root. A rational number is a whole number, a fraction (unless the denominator is 0), a mixed number, or a decimal number. If you had the square root of 4, that would be rational because it can be simplified to 2 or -2. so there for it is a rational number I hope this is what you are looking for.

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PLEASE HELP WITH GEOMETRY WILL GIVE BRAINLIEST

sammy [17]

Answer:

Option D

Step-by-step explanation:

In the first three options we can evaluate the values of x with the help of Sine Rule for all the triangles

The Rule says

$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$

Where a , b and c are the sides opposite to the angles A, B and C of any ΔABC.

Hence , in order to determine unknown values of sides or angles , we need any 3 values from all 3 sides and 3 angles in a triangle. First Three options give us three values but the last option gives only 2.

Example

in first option we can apply Sine Rule as

$\frac{\sin 84}{x}=\frac{\sin 63}{3}$

$\frac{0.994}{x}=\frac{0.891}{3}$

$x=\frac{0.991 \times 3}{0.891}$

$x=\frac{2.973}{0.891}$

$x=3.336$

8 0

3 years ago

at memorial hospital 9 of the 12 babies born on Tuesday were boys In simplest form What fraction of the babies born on Tuesday w

Papessa [141]

9/12 = (9/3) / (12/3)= 3/4.

3/4 of the babies born on Tuesday were boys~

5 0

3 years ago

Read 2 more answers

Which pair of transformations to the figure shown below would produce an image that is on top of the regional

yKpoI14uk [10]

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7 0

3 years ago

Last questions, plz help

Goryan [66]

Answer:

9. $a_n=7+6n$

10. $a_n=a_{n-1}+7$

Step-by-step explanation:

9. Given the sequence

$13, 19, 25, ...$

In this sequence,

$a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...$

Note that

$a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,$

then the common difference in this sequence is $d=6$

You have

$a_1=13\\ \\d=6,$

then the explicit formula is

$a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n$

10. Given the sequence

$-10,-3, 4, 11, ...$

In this sequence,

$a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...$

Note that

$a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,$

then the common difference in this sequence is $d=7$

You have

$a_1=-10\\ \\d=7,$

then the recursive formula is

$a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7$

5 0

3 years ago

Please please help thank you

Tcecarenko [31]

Answer:

b-4^3

Step-by-step explanation:

7 0

3 years ago