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Crank
3 years ago
5

Please help! will give brainliest

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Answer1.79

Step-by-step explanation:

jayfeather friend me

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find a set of parametric equations of the line the line pases through the point (2,3,4) and is parallel to the xz-plane and the
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Answer:

x=2, y=3, z=4+t

Step-by-step explanation:

For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

u= (u_x, u_y, u_z)= (0,0,1)

Or any factor of u but for simplicity let's take the unitary vector.

Then the parametric equations are given by:

x= P_x + u_x t

y= P_y + u_y t

z= P_z + u_z t

Where the point given P=(2,3,4)= (P_x , P_y, P_z)

And then since we have everything we can replace like this:

x= P_x + u_x t 2+ 0*t = 2

y= P_y + u_y t= 3+ 0*t = 3

z= P_z + u_z t = 4+ 1t = 4+t

x=2, y=3, z=4+t

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3 years ago
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