Answer: 11.25 secs
Step-by-step explanation:
So in this sense the rockets origin or the ground is modeled at h=0 so the time required if used on a table shows that h=0 between the values of 11 and 12. So if you plug and chug decimal values between these two values you get exactly 0 at t=11.25 so it takes approximately 11.25 seconds for the rocket to return to the ground
The surface area in this equation is 5x4 which is 20
Answer:
less than, this is scaling dude
Step-by-step explanation:
The answer to 5(2-y)+y=-6
x=4
