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Vladimir [108]
3 years ago
6

Find the measure of an angle that is complementary to

Mathematics
1 answer:
Anton [14]3 years ago
4 0

Answer:

9 degrees

Step-by-step explanation:

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What is 5(−3)(−2) for usatestprep HELPPP
Alex777 [14]

Answer:

<h2>30</h2>

Step-by-step explanation:

5*(-3)(-2)

5*6<em> (negative * negative= positive) </em>

30

hope this helpsssss

3 0
2 years ago
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If 9 is subtracted from two thirds of a number, the result is 7. Find the number
SSSSS [86.1K]

Answer: 24

Step-by-step explanation:

x/2*3-9=7. So you want to know what x is. So lets start reverse thinking. 7+9=16, 16=x/2*3. That means 16 is 2/3 of x. 16/2=8, 8*3=24! The answer is 24.

3 0
3 years ago
Find the area and show all work
____ [38]

Answer:

Area for rectangle = B*H

Area for triangle = B*H/2

total area = area of triangle + area of rectangle

A of rectangle = 17 * 22 = 374 cm²

Triangle height is not giving so we take 22-10 = 12 cm for the height so

A of triangle = 12*19/2 = 114 cm²

total A = 114 + 374 = 488 cm²

Step-by-step explanation:

5 0
4 years ago
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Jeremiah makes 25% of the three-point shots he attempts. For a warm up, Jeremiah likes to shoot three-point
seropon [69]

Answer:

P(M>6)\approx0.178 \approx 0.18P(M>6)≈0.178≈0.18P,

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects
Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have p=10 groups and on each group from j=1,\dots,p=10 we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

And we have this property

SST=SS_{between}+SS_{within}

Solution to the problem

Part a

(i) confidence interval

False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.

(ii) t-test

Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.

(iii) ANOVA

This one is the best method when we want to compare more than 1 group of means.

(iv) Chi square

False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.

Part b

The ANOVA test is more powerful than the t test when we want to compare  group of means.

8 0
4 years ago
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