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zzz [600]
3 years ago
12

A certain bacteria culture grows at a rate of 18% everyday. There are currently 420 bacteria. How many bacteria will there be on

Day 8? Round the answer to the nearest whole number.
Mathematics
2 answers:
spayn [35]3 years ago
4 0

In this question, it is given that

A certain bacteria culture grows at a rate of 18% everyday. There are currently 420 bacteria.

And we have to find number of bacterias on day *.

For that we use the following formula

N(t) =N_{0} (1 +r)^t

N(0)= 420, r = 0.18 , and \ t = 8days

Substituting these values in the formula, we will get

N(8)= 420(1+0.18)^8
\\
N(8)=1579

THerefore on day 8, number of bacterias are 1579.

andreev551 [17]3 years ago
3 0

Answer:

1579

Step-by-step explanation:

I am just confirming that this answer is correct. :D

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The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

np=80*0.1=8

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that  the percentage is lower in this district.

Then, the null and alternative hypothesis are:

H_0: \pi=0.173\\\\H_a:\pi

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.057) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that  the percentage is lower in this district.

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