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Anna71 [15]
2 years ago
5

A pebble falls of a cliff at a height of 256 ft. If the equation for the height as a function is h(t)=-16^2 + initial height whe

re t is time in seconds and h(t) is height in feet, how many seconds will it take for the pebble to hit the ground?
Mathematics
1 answer:
AlladinOne [14]2 years ago
6 0

Answer:

After 4secs

Step-by-step explanation:

Given the function of the height expressed as;

h(t)=-16^2 + initial height

If initial height = 256, then;

h(t) = -16t^2 + 256t

The pebble will hot the ground at when h(t) = 0

Substitute

0 = -16t^2 + 256t

16t^2 = 256

t^2 = 256/16

t^2 = 16

t = 4

Hence the pebble will hit the ground after 4secs

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Step-by-step explanation:

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5 0
2 years ago
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Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​
bearhunter [10]

Answer:

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Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

\sf \log_{10} 3 = 0.4771

To find log₁₀ 6, first rewrite 6 as 3 · 2:

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\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

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\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321

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