A pebble falls of a cliff at a height of 256 ft. If the equation for the height as a function is h(t)=-16^2 + initial height whe
re t is time in seconds and h(t) is height in feet, how many seconds will it take for the pebble to hit the ground?
1 answer:
Answer:
After 4secs
Step-by-step explanation:
Given the function of the height expressed as;
h(t)=-16^2 + initial height
If initial height = 256, then;
h(t) = -16t^2 + 256t
The pebble will hot the ground at when h(t) = 0
Substitute
0 = -16t^2 + 256t
16t^2 = 256
t^2 = 256/16
t^2 = 16
t = 4
Hence the pebble will hit the ground after 4secs
You might be interested in
Answer:
ab and ac are congruent with each other
Answer:
he multiplied by 0.8 not .08
Step-by-step explanation:
when doing 8% you go back 2 places so 0.08
34×0.08= 2.72
34+2.72= 36.72
Answer:
graph attached
Step-by-step explanation:
Log 100 equals 2. If you use a scientific calculator it equals 2.
Answer:
4
Step-by-step explanation:
